corrora & //apploc.dek
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corrora & //apploc.dek presents
"four-core fragment"
The four-core fragment is probably the most in depth departure from mathematical probability. Leading into the possibility that infinity is defined by a sequence that is partially fragmented into a four-core split that is relatively coherent. The client will be developed to understand the static and dynamic formulations in characters that describe itself while, the data is allocated by a molecular string.
It was decided that the molecular string will always be "0000", and inside will be a privated output, with a boolean decryption. This is where the dynamic formulation in characters will open the ouput.
This is why the property is called four-core fragment. Here is the formula:
(d)irect
0000//// +-(O, A) +-((A, O) +-A, O)) unit 1
0000\\\\ +-(A, O) +-(A, A) +-(O, A). unit 2
(s)tatic
0000//// +-(O,A +-A, O) +-(A, O)
0000\\\\ +-(A, O) +-(A, A) +-(O, A).
Example:
Unit 1 is always first and randomly or specifically chosen the second is chosen to cancel itself out.
+(O, A) -(O, A) and +(O, A) -(O, A) = 0
Next step:
+-((A, O and +- A, O)) +- A, O = (A, O) and +-(A, A)
This is then deposited into the memory or "bank", as -(AOAA) +(AOAA) as a point.
Last step: start with the same operation as above.
static:
+-(O, A) and +-(A, O) and +-(O, A) = +-(A, O)
+-(A, O) and +-(A, O)= (A, O)
+-(A, A) = +(A, A) and -(a, a) [lower to smaller a, when there is a secondary and they combine.
+- (AOAOAaAa)
LIST BANK: list twice due to postive and negative inverse.
-AOAA and +AOAO[AaAa]
+AOAA and -AOAO[AaAa]
-AOAA and -AOAO[AaAa]
+AOAA and +AOAO[AaAa]
-AOAA
+AOAO = [+-AO] (x)
+AOAA
-AOAO = [+-AO] (x)
-AOAA
-AOAO = [2AOA, -AO] (y)
+AOAA
+AOAO = [2AOA, +AO] (z)
COMBINE: x*y*z = xyz or x^2yz
xyz = also yz boolean character don't forget that we also have [AaAa] in x*y*z
complete equation: +-(AO) +(A, A)and -(a, a) as such:
GET X:
+AO + A = +AOA
-AO -a = -AOA [-a would then be changed due to the sign change]
+A -a = +Aa (x)
SUPPLY:
x = +(Aa) as a boolean
y = [2AOA, -AO] as a point
z = [2AOA, +AO] as a point
x^2= +[AA, aa] as a point
INTEGRATE CHARACTERS: when reading the solution begin with the last character before the comma if it ends in an A, the solution ends. If it ends in an O, it has not yet ended and continues until the solution ends.
engage:
x | a IMPERIAL: r as boolean P as pattern, X as unknown char
x | 0 + 1/aX
\ |aXaA/OAAX, AaXa
+a, -a, -a | 0000
xyz <xy:z()|00A{r} = aa, r | a [ra, XX]
^
xy/z > ayz() o = ayo
v
oyXa & X | X = Aa(P): 0000l y()x =/00 | y>Aax
0000 >>>> o | a <x <a, x< x | a, X
when an "X" is the end of the solution, any character can be used to connect to the solution.
The ideal situation is to graph the outcome of an infinity to a system. The boolean can be a counter-part to what the solution may represent. This may define the system but not the whole system. The actual dependency is directly responsible to the relation to the formality that the annex is in condition to append:
METRIC SERIAL:
0000<<<< XyOA, XX/(AoAo - XOAA)^2
-AOAO = [2AOA, -AO] (y)
X(-AOAO = [2AOA, -AO] (y)) OA, XX / (Xo)^2
X+(2AOA, -AOOA: XX)
XAOAAOA, -AOOA // {XX} / (Xo)^2
x y z
y = mx + b
-AOOA = (m)XAOAAOA + b: (z / (Xo)^2
-AOOA = (m)XAOAAOA + b: (XX/ (Xo)*(Xo))
(XX/ (XO)^2)
There is no way to find the slope unless to graph, and with the y-intercept a divsior, thus the y-intercept must divide into two different parts. Meaning there is a pause in the line, where it develops a stability.
b: XOO
-AOOA =(m)XAOAAOA + X/OO
There needs to be two more coordinates to demonstrate the slope we have (XAOAAOA, -AOOA) + (x2, y2):
+A -a = +Aa (x)
-AOAO = [2AOA, -AO] (y)
(XAOAAOA, -AOOA) + (Aa, AOAOAOaO)
m =y2 - y1
_______
x2 - x1
AOAOAOaO + AOOA AOAOAOOOA
m= ____________ = _________ = OXOO
Aa - XAOAAOA AXOAAOA
-AOOA = (OXOO)XAOAAOA + XOO
-AOOA = (OXOOAXAOAAOA) + XOO
+AOOA = -(oxooaxaoaaoa) - xoo
EVALUATE:
[oxoo axao aaoa] - xoo[]
[ x x inc. ] - x []end inc. with Aa or [A, A] xModify
[ x x P ] - x []end P as pattern in and/or xModifyTerm
[ x1 x2 X ] +1/x []end X as conjunction in [is] + [xoo(term)]
x1 * x2 * X + 1/xoo AND OR
x1 * x2 * X + 1/x00 is OR (these are two zero)
EVALUATE:
4x + 1/xoo AND OR
4x + 1/x00
AND: 8x/1 + 1/xoo + 1/x00 = 8x/-x^200 = x00/8 [ expressing logic ] 0.25/2 = .125 (right)
2.5/2 = 1.25 (wrong)
.125x0.1250 (.125 + .125)
.125x.250 (.125 + .25) +
.125x0.375 (.125 + .375)
.125x.50 (.125 + .50) +
.125x0.6250 (.125 + .625)
.125x.75 (.125 + .75) +
.125x0.8750 (.125 + .875)
+.125x1 (1 * 1) = 1.0 [8]
OR: The fraction is a conjuction that is separate terms. [example: a:b]
4x + 1/xoo
xxxx XOO[], [] <== conjunction stable
4x + 1/x00
xxxx XXXX, X[] <== inconsistent