Liquid Nitrogen

I'm diving into geometrics. Please note that a + b is 180. I'm sorry for the incoherence in some of the tabs. I keep forgetting the history of my calculator. Sometimes I get related numbers but forget how they got there. I'm thinking the 180 degree part is some kind of triangulation, the ability to find a line or coordinates using triangles.

a = 160

b = 20

c = 2

d = 65

d = a**2 + b**2 :: e / b**2

e = 26000

f = g/a

f = 1625

f = e(b) / c / a

g = 260,000

g = a(f)

g = e(b) / c

a(f) = e(b) / c

a**2 + b**2 = e / b**2

160**2 + 20**2 = 26,000 / 400; 65

a**2 + b**2 = e / b**2 [65]

25,600[a**2] + 400[b**2] = 26,000 / 400 = 65; d;

a**2 + b**2 = e(b) / c / a((f = e :: b / c)) = 260,000

25600 + 400 = 26,000(20) / 2 / 160 = 160(1625) = 260,000)

f = e(b) / c / a = e(b) / c / a = 1625

1625 = 26,000 / 2 / 160 =

f = 1625 * a = e(b) / c / a((f = e :: b / c )) = 260,000

a(f) = e(b) / c

160(1625) = 260,000(20) / (2)

a(f) = a(f = e :: b / c)

1625 = 26,000(20) / 2 / 160 = 26,000(20) / 2 / 160 = f

a = 120 >> a + b = 180

b = 60 >> a + b = 180

c = 2

d = 5: a**2 + b**2 = e / b**2 = d or a**2 + b**2 :: e / b**2

d = 5

e = 18,000

f = 4500

f = e(b) / c / a

g = 540,0000

g = a(f)

g = e(b) / c

a(f) = e(b) / c

120**2 + 60**2 = 18,000 / 3600 = 5; d;

f = 4500

a(f) = e(b) / c

540,000 = 540,0000

a = 150

b = 30

c = 2

d = 26: a**2 + b**2 = e / b**2 = d or a**2 + b**2 :: e / b**2

d = 26

e = 23400

f = g / a

f = e(b) / c / a

g = 351,000

a(f) = e(b) / c

g = a(f)

g = e(b) / c

a**2 + b**2 = e / b**2 = 26

22,500 + 900 = 23400 / 900 = 26

22,500 + 900 = 23400 /

a(f) = e(b) / c

150(2340) = 23400(30) / 2

351,000 = 702,000 / 2

351,000 = 351,000

I'm going to take this moment to clean up the Python tab:

6 as INT; i=4

((int * (int + 1)) + (5(i) - int * (int + 1) / 2) * (5 + 2)i) = X

((INT * (INT + 1)) + (5(I) - INT * (INT + 1 ) / 2) * (5 + 2)I) = X

6 * (6 + 1) + ((5(4)) - ((6 * (6 + 1)) / 2 *(5 + 2)4) =
42 + 20 - 42 / 2 * 5 * 4 * 4 * 2 = 208

6 as INT; i=4

y = ((2i + 5i) + int * (int + 1)) + 5i - int * (int + 1)

y = ((28) + 6 * (6 + 1)) + 5(4) - 6 * (6 + 1)
28 + 42 + 20 - 42
((70) + 20 - 42)

y = 20 * 2 + (8) = 48;

I didn't data mine into C1 and C2.

C1 = X * 0.5 - i**2 - i**2
X = X [50, 156, 208, 260, 312] [i = 2, 3, 4, 5, 6]

C2 = X * 0.5 + i**2 + i**2
X = X [50, 156, 208, 260, 312] [i = 2, 3, 4, 5, 6]

10 * (5 * i) + (2 * i); i = [2, 3, 4, 5, 6]

2: 10 * (5 * 2) + (2 * 2)=
10 * 4 + 10 = 50

!! 156 - 50 is not 52 increment like 312 - 260, 260 - 208...!!

-- The "10" is from X equation, when you do the math, there will be a static 10 in each increment when doing the math, the only thing that really changes is the i = [2, 3, 4, 5, 6]

3: 10 * (5 * 3) + (2 * 3)=
10 * 15 + 6 = 156
4: 10 * (5 * 4) + (2 * 4)=
10 * 20 + 8 = 208
5: 10 * (5 * 5) + (2 * 5)=
10 * 25 + 10 = 260
6: 10 * (5 * 6) + (2 * 6)=
10 * 30 + 12 = 312

((2i + 5i) + 5i); i = [2, 3, 4, 5, 6]

2a: ((2(2) + 5(2) + 5(2)=
4 + 10 + 10 = 24
3a: ((2(3) + 5(3) + 5(3)=
6 + 15 + 15 = 36
4a: ((2(4) + 5(4) + 5(4)=
8 + 20 + 20 = 48
5a: ((2(5) + 5(5) + 5(5)=
10 + 25 + 25 = 60
6a: ((2)(6) + 5(6) + 5(6)=
12 + 30 + 30 = 72

!! ^^ all real numbers are incremented !!

Scope:

X = [50, 156, 208, 260, 312]

2b to 6b: (0.5x) - (i**2 + i**2); X = [50], i = [2, 3, 4, 5, 6]
2b1 to 6b1:(0.5x) + (i**2 + i**2); X = [50], i = [2, 3, 4, 5, 6]

2b + 2b1 = 50;
3b + 3b1 = 50;
4b + 4b1 = 50;
5b + 5b1 = 50;
6b + 6b1 = 50;

2b.a to 6b.a: (0.5x) - (i**2 + i**2); X = [156], i = [2, 3, 4, 5, 6]
2b.2a to 6b2.a: (0.5x) + (i**2 + i**2); X = [156], i = [2, 3, 4, 5, 6]

2b.a + 2b2.a = 156;
3b.a + 3b2.a = 156;
4b.a + 4b2.a = 156;
5b.a + 5b2.a = 156;
6b.a + 6b2.a = 156;

2b.b to 6b.b: (0.5x) - (i**2 + i**2); X = [208], i = [2, 3, 4, 5, 6]
2b2.b to 6b2.b (0.5x) + (i**2 + i**2); X = [208], i = [2, 3, 4, 5, 6]

2b.b + 2b2.b = 208;
3b.b + 3b2.b = 208;
4b.b + 4b2.b = 208;
5b.b + 5b2.b = 208;
6b.b + 6b2.b = 208;

2b.c to 6b.c: (0.5x) - (i**2 + i**2); X = [260], i = [2, 3, 4, 5, 6]
2b2.c to 6b2.c: (0.5x) + (i**2 + i**2); X = [260], i = [2, 3, 4, 5, 6]

2b.c + 2b2.c = 260;
3b.c + 3b2.c = 260;
4b.c + 4b2.c = 260;
5b.c + 5b2.c = 260;
6b.c + 6b2.c = 260;

2b.d to 6b.d: (0.5x) - (i**2 + i**2); X = [312], i = [2, 3, 4, 5, 6]
2b2.d to 6b2.d: (0.5x) + (i**2 + i**2); X = [312], i = [2, 3, 4, 5, 6]

2b.d + 2b2.d = 312;
3b.d + 3b2.d = 312;
4b.d + 4b2.d = 312;
5b.d + 5b2.d = 312;
6b.d + 6b2.d = 312;

INT = 6, i = 2

-- The only thing that changes is the first two terms. In each block, the 6th and 7th terms are the same in each block.

(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i)
(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 2b2.b) * (2 * i) + (5 * i)
(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 2b2.b) * (2 * i) + (5 * i)
(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)
(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 2b2.b) * (2 * i) + (5 * i)
(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 3b.c) * (2 * i) + (5 * i)
(2b2.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)

+ 10 * 4 + 10
= 50;

(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i)
(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 2b2.b) * (2 * i) + (5 * i)
(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 2b2.b) * (2 * i) + (5 * i)
(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)
(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 2b2.b) * (2 * i) + (5 * i)
(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 3b.c) * (2 * i) + (5 * i)
(3b2.b - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)

= 50;

(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i)
(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 2b2.b) * (2 * i) + (5 * i)
(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 2b2.b) * (2 * i) + (5 * i)
(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)
(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 2b2.b) * (2 * i) + (5 * i)
(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 3b.c) * (2 * i) + (5 * i)
(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)

= 50;

(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i)
(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 2b2.b) * (2 * i) + (5 * i)
(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 2b2.b) * (2 * i) + (5 * i)
(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)
(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 2b2.b) * (2 * i) + (5 * i)
(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 3b.c) * (2 * i) + (5 * i)
(3b2.b - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)

= 50;

(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i)
(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 2b2.b) * (2 * i) + (5 * i)
(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 2b2.b) * (2 * i) + (5 * i)
(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)
(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 2b2.b) * (2 * i) + (5 * i)
(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (3b2.b - 3b.c) * (2 * i) + (5 * i)
(2b.c - 2b2.b) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b.c - 3b.c) * (2 * i) + (5 * i)

= 50;

i = 2

-- Note the first and second term changes, with the exception of the switched order of 2 * i and 5 * i to 5 * i and 2 * i

(2b.c - 3b.c) * (5 * i) + (2 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i) = 50;

(2b.c - 3b.c) * (2 * i) + (5 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (5 * i) + (2 * i) = 104;

(2b2.c - 3b.c) * (2 * i) + (5 * i) - 6^3 + 3b.c + (2b2.c - 3b.c) * (2 * i) + (5 * i) = 86;

3b.b: X * 0.5 - 3 * 2 + 3 * 2;

3b.b = 86;

2b2.a: X * 0.5 + 2 * 2 + 2 * 2;

2b2.a = 86;

10 * (2 * 2) + (5 * 2) = 50;
10 * (5 * 2) + (2 * 2) = 104;

2b2.c - 3b.c * (2 * 2) + (5 * 2) = 50
3b2.b - 3b.c * (2 * 2) + (5 * 2) = 50
2b.c - 3b.c * (2 * 2) + (5 * 2) = 50

2b2.c - 3b.c * (5 * 2) + (2 * 2) = 104
3b2.b - 3b.c * (5 * 2) + (2 * 2) = 104
2b.c - 3b.c * (5 * 2) + (2 * 2) = 104

2b2.c - 2b2.b * (2 * 2) + (5 * 2) = 50
3b2.b - 2b2.b * (2 * 2) + (5 * 2) = 50
2b.c - 2b2.b * (2 * 2) + (5 * 2) = 50

2b2.c - 2b2.b * (5 * 2) + (2 * 2) = 104
3b2.b - 2b2.b * (5 * 2) + (2 * 2) = 104
2b.c - 2b2.b * (5 * 2) + (2 * 2) = 104

INT = 6

104 - 50 = 54

5b.b: X * 0.5 - 5**2 + 5**2
0.5x - 25 + 25 =
104 - 50 = 54
5b.b = 104 - 50

= 54
= 54 / 9 = INT: [6]

54 + 104 = 158
       21632
       416
           = 52;
           5b.b: 54
           5b.b + [variable](208 / 2) = 158;
[variable: 104]

5b.b + 104(208 / 2) = 52
54 + 21632 / 416 = 52
52 * 9 = 468 / 6 = 78
78 / 6 = 13 [PRIME]

13 * 6**2 = 468;